Not derived a formula , but i know a logic.
Firstly 1 is an odd number ,
Secondly 256-254=2 , adding 1 to any multiple of 2 will always give an
odd number
Hence it matches any odd network and subnets of that network(due to
the .255.255.255 )
To match only odd networks with no subnets you can use
1.0.0.0 254.0.0.0
HTH
On 3/23/10, Tannie Philly <tanniephilly_at_gmail.com> wrote:
> Hi all,
>
> Please I need someone to help me out in explaining how to derive odd\even
> prefixes (wildcards).
>
> Forinstance,
> ip aceess-list standard ODD_FIRST_OCTET
> permit 1.0.0.0 254.255.255.255
>
> Is there a formular for arriving at this wildcard?
>
> Please I need assistance here.
>
> Tannie
>
>
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-- Warm Regards, Eseosa CCIE #23782 "The Christian is a person who makes it easy for others to believe in God." - Robert M. McCheyne Blogs and organic groups at http://www.ccie.netReceived on Tue Mar 23 2010 - 17:30:09 ART
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