From: Trinh Khac Cong (congtk@yahoo.com)
Date: Thu Dec 18 2008 - 09:38:19 ARST
It means you have to div 3200 with number of interval.
With default tc(125),
the number of interval is:
1000ms/125 = 8, then
bc = 32000/8 = 4000
Best,
Cong Trinh
________________________________
From: Amr <amr.ccie@gmail.com>
To: ccielab <ccielab@groupstudy.com>
Sent: Thursday, December 18, 2008 1:30:33
AM
Subject: IEWB-VOL2 LAB1 task 7.2
Dear All,
The question says
that to allow burst of 1/4 th of this rate
(128Kbps) when configuring frame
relay traffic shaping on the serial
interface
So should the Bc here is equal
to 128000/4 = 32000 not 4000 as in the
solution guide
So the configuration
must be as below
R1#sh policy-map ICMP
Policy Map ICMP
Class ICMP
police cir 128000 bc 32000
conform-action transmit
exceed-action
drop
Please Advice
Thanks In Advance
Blogs and organic groups at
http://www.ccie.net
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