From: But Nicky (lyredhair@gmail.com)
Date: Thu Dec 18 2008 - 13:14:36 ARST
Hi Cong,
The unit for burst interval is "BYTE" not "BIT", so that you must divide
"8".
Regards,
But Nguyen
On Thu, Dec 18, 2008 at 6:38 PM, Trinh Khac Cong <congtk@yahoo.com> wrote:
> It means you have to div 3200 with number of interval.
>
> With default tc(125),
> the number of interval is:
> 1000ms/125 = 8, then
> bc = 32000/8 = 4000
>
> Best,
> Cong Trinh
>
>
>
>
> ________________________________
> From: Amr <amr.ccie@gmail.com>
> To: ccielab <ccielab@groupstudy.com>
> Sent: Thursday, December 18, 2008 1:30:33
> AM
> Subject: IEWB-VOL2 LAB1 task 7.2
>
> Dear All,
>
> The question says
> that to allow burst of 1/4 th of this rate
> (128Kbps) when configuring frame
> relay traffic shaping on the serial
> interface
>
> So should the Bc here is equal
> to 128000/4 = 32000 not 4000 as in the
> solution guide
>
> So the configuration
> must be as below
>
> R1#sh policy-map ICMP
> Policy Map ICMP
> Class ICMP
>
> police cir 128000 bc 32000
> conform-action transmit
> exceed-action
> drop
>
>
>
> Please Advice
>
> Thanks In Advance
>
>
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>
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>
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