From: abderrahim sadki (a_sadki1@hotmail.com)
Date: Sun Sep 09 2007 - 05:17:15 ART
hi
In this task 2 acl are required
one matching 224.0.0.0/5 the other matching 232.0.0.0/5
the solution shows this for 224.0.0.0/5:
ip access-list standard GROUP_224
permit 224.0.0.0 7.255.255.255
and for 232.0.0.0/5
ip access-list standard GROUP_232
permit 232.0.0.0 3.255.255.255
permit 236.0.0.0 1.255.255.255
permit 238.0.0.0 0.255.255.255
can someone explain this to me?
Thanks
Abderrahim
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