Re: QOS dual policer

Adam,

Thanks always the simple stuff I miss

On Fri, Mar 25, 2011 at 3:12 PM, Adam Means <ameans.ece02_at_gtalumni.org>wrote:

> bc = CIR*Tc = 512kbits*.03s = 15360bits = 1920bytes. Similar for be.
>
> On Fri, Mar 25, 2011 at 2:03 PM, Bryan Stair <uptown.ccie_at_gmail.com>wrote:
>
>> Everybody,
>>
>> This may seem like a basic question but I am struggling with making sense
>> out of it, so don't beat up on me too much. I working on a lab that states
>> the following:
>>
>> Traffic Policer
>>
>> CIR 512K
>> EIR/PIR 384K
>> TC 30ms
>>
>> Implement traffic policing on router's inbound connection using dual rate
>> policer with exceed and violate actions. Now I understand the dual rate
>> policer, but I am struggling with calculating the bc/be values.
>>
>> police-map DROP_P2P
>> class class-default
>> police cir 512000 bc 1920 pir 896000 be 3360 conform-action <x>
>> exced-action<y> violate-action drop
>>
>> I read somewhere that the bc values are calculated as such
>>
>> bc= (CIR*TC) + (MTU*8kpbs)
>>
>> I'm not sure how they arrived at that value. Can anyone shed any light?
>>
>> Thanks
>>
>>
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Received on Fri Mar 25 2011 - 16:02:01 ART