Re: QOS dual policer

bc = CIR*Tc = 512kbits*.03s = 15360bits = 1920bytes. Similar for be.

On Fri, Mar 25, 2011 at 2:03 PM, Bryan Stair <uptown.ccie_at_gmail.com> wrote:

> Everybody,
>
> This may seem like a basic question but I am struggling with making sense
> out of it, so don't beat up on me too much. I working on a lab that states
> the following:
>
> Traffic Policer
>
> CIR 512K
> EIR/PIR 384K
> TC 30ms
>
> Implement traffic policing on router's inbound connection using dual rate
> policer with exceed and violate actions. Now I understand the dual rate
> policer, but I am struggling with calculating the bc/be values.
>
> police-map DROP_P2P
> class class-default
> police cir 512000 bc 1920 pir 896000 be 3360 conform-action <x>
> exced-action<y> violate-action drop
>
> I read somewhere that the bc values are calculated as such
>
> bc= (CIR*TC) + (MTU*8kpbs)
>
> I'm not sure how they arrived at that value. Can anyone shed any light?
>
> Thanks
>
>
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Received on Fri Mar 25 2011 - 15:12:23 ART