From: Bill Eyer (beyer@optonline.net)
Date: Wed Aug 27 2008 - 08:05:00 ART
Nitro,
You didn't include a config here, but I can offer one possible
explaination. When you redistribute one routing protocol into another,
all interfaces that are in that routing protocol come along with the
redistribution automatically EXCEPT under one circumstance. That
circumstance is when you have another interface on that same router that
is redistrbuted into the destination protocol as connected.
In other words if you have a router with RIP in 2 interfaces, OSPF in 2
interface and one connected interface that isn't in any protocol but is
redistributed into RIP, then your other 2 interfaces that are in OSPF
will NOT automatically be redistributed into RIP when you redistibute
OSPF into RIP, you have to manually redistribute all connected
interfaces once you redistribute any of them.
Bill
Nitro Drops wrote:
> Guys,
>
> A bit lost on this redistribution.
>
>
> router ripredistribute connected metric 1 route-map CONNECTED>RIPredistribute ospf 1 metric 1route-map CONNECTED>RIP permit 10match interface Ethernet0/0 Loopback0/0 Serial1/2 Serial1/3 Serial1/0
>
>
> Q1.) Why is there a need to redistribute connected interfaces of R3's s1/2, s1/3, s1/0 into RIP since they are advertised in OSPF domain? In the previous labs when doing redistribution RIP and OSPF, i dont remember redistributing those interfaces (already advertised in OSPF domain) as connected interfaces into RIP. Is there a reason for this?
>
> When i do a show IP route for these interfaces s1/2, s1/3, s1/0 on R3, they are known as connected routes instead of OSPF routes, is that the reason why these connected interfaces are required to be redistributed manually into RIP domain. How come R3's E0/1 (already advertised in RIP domain) does not need to be redistributed as connected into OSPF domain?
>
> Any kind advices are appreciated.
>
> Ta
> Nit
>
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