From: Darby Weaver (darbyweaver@yahoo.com)
Date: Wed Dec 19 2007 - 20:11:33 ART
Think of it this way:
7 = 0000 0111 in binary.
So...
7 5 3 1
Are the numbers you are looking for.
--- "Smithson, Brandon K "
<brandon.k.smithson@citi.com> wrote:
> Actually, doesn't that just filter 1,3,5 and 7?
>
> Start ip = 1 = 00000001
> Mask = 6 = 00000110
>
> That gives possible choices of:
> 00000001 = 1
> 00000011 = 3
> 00000101 = 5
> 00000111 = 7
>
> Since the starting IP is 1 and the mask has a 0 bit
> in that position,
> any other filtered ip must always be an odd number.
>
>
> -----Original Message-----
> From: nobody@groupstudy.com
> [mailto:nobody@groupstudy.com] On Behalf Of
> Edison Ortiz
> Sent: Wednesday, December 19, 2007 9:11 AM
> To: 'Lora Ganeva'; 'shiran guez'
> Cc: ccielab@groupstudy.com
> Subject: RE: rip networks filtering
>
> No, that filters network 199.16.1.0-199.16.7.255 on
> the first ACL and
> 199.16.8.0-.255 on the second ACL - not just even
> networks.
>
>
>
> Unless I misunderstood the requirement, that should
> cover it.
>
>
>
> Edison Ortiz
>
> Routing and Switching, CCIE # 17943
>
> _____
>
> From: Lora Ganeva [mailto:lganeva@mobiltel.bg]
> Sent: Wednesday, December 19, 2007 9:53 AM
> To: Edison Ortiz; shiran guez
> Cc: ccielab@groupstudy.com
> Subject: RE: rip networks filtering
>
>
>
> This filters all even networks:-(
>
>
>
> From: Edison Ortiz [mailto:edisonmortiz@gmail.com]
> Sent: 19 dEKEMWRI 2007 G. 16:43
> To: Lora Ganeva; 'shiran guez'
> Cc: ccielab@groupstudy.com
> Subject: RE: rip networks filtering
>
>
>
> 199.16.1.0 0.0.6.255
>
> 199.16.8.0 0.0.0.255
>
>
>
> Edison Ortiz
>
> Routing and Switching, CCIE # 17943
>
> -----Original Message-----
> From: nobody@groupstudy.com
> [mailto:nobody@groupstudy.com] On Behalf Of
> Lora Ganeva
> Sent: Wednesday, December 19, 2007 8:44 AM
> To: shiran guez
> Cc: ccielab@groupstudy.com
> Subject: RE: rip networks filtering
>
>
>
> Hi all,
>
>
>
>
>
>
>
> But 199.16.1.0 0.0.7.255??? this is actually
> 199.16.0.0 0.0.7.255 and
> the zero
>
> subnet has to be filtered.
>
>
>
>
>
>
>
> BR,
>
>
>
> Lora
>
>
>
>
>
>
>
> From: shiran guez [mailto:shiranp3@gmail.com]
>
> Sent: 19 dEKEMWRI 2007 G. 15:15
>
> To: Lora Ganeva
>
> Cc: ccielab@groupstudy.com
>
> Subject: Re: rip networks filtering
>
>
>
>
>
>
>
> my mistake didnt saw the range sign
>
>
>
>
>
>
>
> Subodh given you the correct answer!
>
>
>
> On Dec 19, 2007 2:11 PM, Lora Ganeva
> <lganeva@mobiltel.bg> wrote:
>
>
>
> Hi experts,
>
>
>
>
>
>
>
> I am experiencing some problems with the following
> task:
>
>
>
>
>
>
>
> Two routers , let's say R1 and R2 are connected
> (media is not important,
>
> let's say it is Ethernet)
>
>
>
>
>
>
>
> R1 Eth1/0---------------150.1.1.0/24-------------
> Eth1/0 R2
>
>
>
>
>
>
>
> R1:
>
>
>
>
>
>
>
> Eth1/0
>
>
>
> Ip add 150.1.1.1 <http://150.1.1.1/> 255.255.255.0
> <http://255.255.255.0/>
>
>
>
>
>
>
>
> R2:
>
>
>
> Eth1/0
>
>
>
> Ip add 150.1.1.2 <http://150.1.1.2/> 255.255.255.0
> <http://255.255.255.0/>
>
>
>
>
>
>
>
> Routers are running rip and R2 is advertising the
> following networks to
>
> R1
>
>
>
>
>
>
>
>
>
>
>
> 199.16.0.0/24
>
>
>
> 199.16.1.0/24
>
>
>
> 199.16.2.0/24
>
>
>
> 199.16.3.0/24
>
>
>
> 199.16.4.0/24
>
>
>
> 199.16.5.0/24
>
>
>
> 199.16.6.0/24
>
>
>
> 199.16.7.0/24
>
>
>
> 199.16.8.0/24
>
>
>
> 199.16.10.0/24
>
>
>
> 199.16.11.0/24
>
>
>
> 199.16.12.0/24
>
>
>
> 199.16.13.0/24
>
>
>
> 199.16.14.0/24
>
>
>
> 199.16.15.0/24
>
>
>
>
>
>
>
> The task requires by configuring only R1 (not
> interface level command)
>
> to allow with an ACL with only 2 lines the following
> subnets:
>
>
>
>
>
>
>
>
>
>
>
> 199.16.1.0/24 - 199.16.8.0/24
>
>
>
>
>
>
>
> I have though a lot of any kind of ACLs but i still
> haven't come to a
>
> good solution.
>
>
>
>
>
>
>
> Any help will be appreciated,
>
>
>
>
>
>
>
> Thanks,
>
>
>
> Lora
>
>
>
>
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