From: Ben (bmunyao@gmail.com)
Date: Wed Sep 05 2007 - 14:28:22 ART
Hi ccie1101,
You may want to verify if f0/15 is the L3 interface on SW2 connecting to R1.
Sincerely
Ben
On 9/5/07, ccie1101 <ccie1101@gmail.com> wrote:
>
> *SW2*
> int fa0/15
> ip summary-address eigrp 100 150.1.4.0 255.255.254.0
> !
> router eigrp 100
> redistribute ospf 1 metric 10000 100 255 1 1500
> !
> router ospf 1
> redistribute eigrp 100 subnets
> !
> !
> SW2 --- ethernet segment --- R1
>
> 1) My question is that when I do a 'sh ip route 150.1.4.0' on R1, which is
> a
> directly
> connected neighbor for SW2, the distance shown is 90 and not 5 ? Why is
> this so as the
> route coming to R1 is an EIGRP summary address which should have an AD
> of
> 5 ?
>
> Here is the *'sh ip route 150.1.4.0' on R1* which is the neighbor for SW2.
>
>
> ------------------------------------------------------------------------------------------------
>
> Known via "eigrp 100", distance 90, metric 514560, type internal
> Redistributing via eigrp 100
> Last update from 164.1.18.8 on FastEthernet 0/0, 00:00:51 ago
>
>
> ------------------------------------------------------------------------------------------------
>
> 2) Also I would like to confirm that it is not necessary to add the AD of
> 5
> behind the summary-address in EIGRP because by default it is 5
> right? which
> would mean the following command should be good enough without adding the
> AD
> of 5 at the end ?
>
> ip summary-address eigrp 100 150.1.4.0 255.255.254.0 *5*
>
> Pls advice,
>
> ccie1101.
>
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