From: ccie1101 (ccie1101@gmail.com)
Date: Wed Sep 05 2007 - 06:28:27 ART
*SW2*
int fa0/15
ip summary-address eigrp 100 150.1.4.0 255.255.254.0
!
router eigrp 100
redistribute ospf 1 metric 10000 100 255 1 1500
!
router ospf 1
redistribute eigrp 100 subnets
!
!
SW2 --- ethernet segment --- R1
1) My question is that when I do a 'sh ip route 150.1.4.0' on R1, which is a
directly
connected neighbor for SW2, the distance shown is 90 and not 5 ? Why is
this so as the
route coming to R1 is an EIGRP summary address which should have an AD of
5 ?
Here is the *'sh ip route 150.1.4.0' on R1* which is the neighbor for SW2.
------------------------------------------------------------------------------------------------
Known via "eigrp 100", distance 90, metric 514560, type internal
Redistributing via eigrp 100
Last update from 164.1.18.8 on FastEthernet 0/0, 00:00:51 ago
------------------------------------------------------------------------------------------------
2) Also I would like to confirm that it is not necessary to add the AD of 5
behind the summary-address in EIGRP because by default it is 5 right? which
would mean the following command should be good enough without adding the AD
of 5 at the end ?
ip summary-address eigrp 100 150.1.4.0 255.255.254.0 *5*
Pls advice,
ccie1101.
This archive was generated by hypermail 2.1.4 : Sat Oct 06 2007 - 12:01:09 ART