RE: IPV6 subnetting question

From: Scott Morris (swm@emanon.com)
Date: Wed Oct 18 2006 - 10:06:32 ART


Site local and link local are two different things...

Link local is FE80:0:0:0::/64 eui-64 by default

Site local is FEC0:0:0:x::/64 eui-64 (or specify host address) but 'x'
represents 16 bits of subnet ID.

Therefore the first 48 bits are set (FEC0:0000:0000::). But yes, since the
question/scenario said pull the subnet ID (16-bit area in IPv6) from the
third octet of the IPv4 address (only 8 bits here) that's where it all fell
in.

HTH,

 
Scott Morris, CCIE4 (R&S/ISP-Dial/Security/Service Provider) #4713, JNCIE
#153, CISSP, et al.
CCSI/JNCI-M/JNCI-J
IPExpert VP - Curriculum Development
IPExpert Sr. Technical Instructor
smorris@ipexpert.com
http://www.ipexpert.com
 
 

-----Original Message-----
From: nobody@groupstudy.com [mailto:nobody@groupstudy.com] On Behalf Of Ivan
Sent: Wednesday, October 18, 2006 4:34 AM
To: ccielab@groupstudy.com; johngibson1541@yahoo.com
Subject: Re: IPV6 subnetting question

SubscriberID first 32 bits (link-local FE80) Network part next 16 bits
SubNetwork part bits 48-64 Host part of IPv6 is last 64 bits.

Therefore Subnetwork part get from third octet of IPv4 235, and host part
get from last octet 2.

> I don't understand.
>
> "fe" is the first octet, "c0" is the second octet.
>
> How could "EB" at the third octet ?
>
>
> John
>
> _______________________________________________________________________
> Subscription information may be found at:
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-- 
Ivan


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