RE: RE: IPV6 subnetting question

From: srdja blagojevic (srdja1@pexim.co.yu)
Date: Wed Oct 18 2006 - 03:22:24 ART


235 = 128 + 64 + 32 + 8 + 2 + 1 = 1110 1011 = EB

hth,
Srdja

-----Original Message-----
From: nobody@groupstudy.com [mailto:nobody@groupstudy.com] On Behalf Of
johngibson1541@yahoo.com
Sent: Wednesday, October 18, 2006 05:50
To: ccielab@groupstudy.com
Subject: Re: RE: IPV6 subnetting question

I don't understand.

"fe" is the first octet, "c0" is the second octet.

How could "EB" at the third octet ?

John



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