From: Jody Davis \(joddavis\) (joddavis@cisco.com)
Date: Sat Aug 13 2005 - 13:20:12 GMT-3
As an example..
Filter only even routes from the 192.168.0.0..
Access-list 1 permit 192.168.0.0 0.0.1.0 (because the "3rd" octet of
address is "0" or an even, and the "1's" bit of the inverse mask is set
to "don't care", all evens will come through..
For odds,
Access-list 1 permit 192.168.1.0 0.0.1.0
Jody
-----Original Message-----
From: nobody@groupstudy.com [mailto:nobody@groupstudy.com] On Behalf Of
Leigh Harrison
Sent: Saturday, August 13, 2005 10:59 AM
To: ccielab@groupstudy.com
Subject: Even/Odd route filtering
All,
If I have the subnet 10.1.n.n - 10.50.n.n and I wanted to filter even
routes out of one interface and odd routes out of a different one, how
would I achieve this?
I know that all I would need to do is match on the 16th bit and ensure
that it is a "1" or a "0" in order to make it odd or even. I know that
I could write a big list, but I would like to match on the one bit. Is
this even possible ?!
Many thanks in advance,
LH
Leigh Harrison
Technical Consultant
Azzurri Communications
Castleton Mill,
Castleton Close,
Leeds,
LS12 2DS
Email: Leigh.Harrison@azzu.co.uk <mailto:Leigh.Harrison@azzu.co.uk>
Mobile: 07989 605 806
Office: 0870 410 5868
Fax: 0870 410 0003
Web: www.azzu.co.uk <http://www.azzu.co.uk/>
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