From: Mike Calhoon (mcalhoon27@gmail.com)
Date: Thu Jun 16 2005 - 09:16:39 GMT-3
Your one line answer will also filter the following hosts:
49.1.0.1
49.1.0.9
If those hosts are not supposed to be filtered, then you will get the
problem wrong. The two line answer will only filter what is required.
Mike
-----Original Message-----
From: nobody@groupstudy.com [mailto:nobody@groupstudy.com] On Behalf Of hin
ccie
Sent: Thursday, June 16, 2005 8:00 AM
To: ccielab@groupstudy.com
Subject: Minimum amount of lines used -> to filter , Pls help TIA
Hi Guys,
I'm rather confused about this issue
- to filter the following hosts with the minimum amount of lines
49.3.0.1
49.5.0.1
49.7.0.1
49.3.0.9
49.5.0.9
49.7.0.9
At first, I come up with one line
49.1.0.1 wild-mask 0.6.0.8
for the second octet summarization
3 = 0 0 1 1
5 = 0 1 0 1
7 = 0 1 1 1
-----------------------
result = octet -> 1 with wild card 6
for the fourth octet summarization
1 = 0 0 0 1
9 = 1 0 0 1
---------------------
result = octet -> 1 with wild card 8
However , there's other opinion with 2 lines
49.3.0.1 wild-mask 0.0.0.8
49.5.0.1 wild-mask 0.2.0.8
which one is right - or there's any other best answer ?
TIA
hin
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