From: hin ccie (hinccie@yahoo.com)
Date: Thu Jun 16 2005 - 09:00:16 GMT-3
Hi Guys,
I'm rather confused about this issue
- to filter the following hosts with the minimum amount of lines
49.3.0.1
49.5.0.1
49.7.0.1
49.3.0.9
49.5.0.9
49.7.0.9
At first, I come up with one line
49.1.0.1 wild-mask 0.6.0.8
for the second octet summarization
3 = 0 0 1 1
5 = 0 1 0 1
7 = 0 1 1 1
-----------------------
result = octet -> 1 with wild card 6
for the fourth octet summarization
1 = 0 0 0 1
9 = 1 0 0 1
---------------------
result = octet -> 1 with wild card 8
However , there's other opinion with 2 lines
49.3.0.1 wild-mask 0.0.0.8
49.5.0.1 wild-mask 0.2.0.8
which one is right - or there's any other best answer ?
TIA
hin
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This archive was generated by hypermail 2.1.4 : Wed Jul 06 2005 - 14:43:41 GMT-3