From: Nico van Niekerk (nico@vanniekerk.co.za)
Date: Tue Oct 19 2004 - 02:16:58 GMT-3
145.x.0.0/16 with x being any number is the same as saying 145.0.0.0/8
Once you specify 'any' number in second octet with a /16 mask you're
actually specifying a mask of /8.
> -----Original Message-----
> From: nobody@groupstudy.com [mailto:nobody@groupstudy.com]On Behalf Of
> Cisco Net
> Sent: Tuesday, 19 October 2004 2:31 PM
> To: Group Study
> Subject: Access-list clarification
>
>
> Hi
> How to write an acl for the following,
> 145.X.0.0 /16 where as second octet can be any number
>
> Got confused..
>
> 145.0.0.0 0.255.255.255 will not match the mask.
>
> Is it,
>
> 145.0.0.0 0.255.255.255 host 255.255.0.0 ???
>
> Please clarify....
> Regards
> Cert
>
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