From: alsontra@hotmail.com
Date: Fri Mar 19 2004 - 12:13:31 GMT-3
Hi Ahmed,
This task is a bit confusing, and may need to be reworded. Here's how I
interpreted tasks 9.1-6
Task 9.1 tells you that your going to be doing FTRS on R1
Task 9.2 tells you that R1 has a Port Speed of 512k
Task 9.3 tells you that R1 has a CIR of 256k
Task 9.4 tells you that R1 should (meaning, change the CIR to) send data at
384k and throttle down to a CIR of 256k. <------ (This would have been
easier to understand if they had said min CIR of 256k. This is the key task-
You've just been told to use 384k as the CIR and 256k as the minCIR.
Task 9.5 tells you that R1 should be allowed to burst up to port speed.
Task 9.6 tells you that your TC=100ms
Here's how I broke it down.
Tc= 1000/100= 10
CIR = 384000
Bc = 384000/10 = 38400
Be= (512000-384000)/10=12800
minCIR= 256000
Turn on adaptive shaping and your done. I admit that I'm making an
assumption on the CIR and minCIR, but I think this question comes done to
interpretation. Perhaps, I just got luck on this task! Hopefully the
Brian's will provide us with further insight.
Alsontra-
----- Original Message -----
From: "Ahmed Mustafa" <ahmed.mustafa@sbcglobal.net>
To: <ccielab@groupstudy.com>
Sent: Thursday, March 18, 2004 11:14 PM
Subject: Internetwork Lab 5 Task 9.1 - 9.5
> Group,
>
> Can someone explain the following:
>
> Task 9.3 clearly says CIR is 256000
> Task 9.5 states Burst up to its port speed. Bc: Wouldn't we simply use
> 512000 for Bc instead of calculating through the formula: BC=CIR * Tc/1000
>
>
> The solution guide states
>
> AR (port speed) = 512000 bps -------> agreed
> CIR (average rate) = 384000bps -------------> if task clear says that
CIR
> 25600, then how to identify the correct CIR value. The task 9.4 states R1
> should send data at 384000.
>
> Solution guide has also defined the Be eventhough is not asked to
configured.
>
> Regards,
>
> Ahmed
>
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