From: Nathaly Landry (lnathaly@cisco.com)
Date: Tue Feb 17 2004 - 12:37:18 GMT-3
If you leave it blank wouldn't the default get applied and you
would end up with a ratio of 2:1??
nat
-----Original Message-----
From: nobody@groupstudy.com [mailto:nobody@groupstudy.com] On Behalf Of
Paul Chen
Sent: Monday, February 16, 2004 8:56 PM
To: ccielab@groupstudy.com
Subject: dllsw load balancing
Hi All,
At the following link:
http://www.cisco.com/warp/public/cc/pd/ibsw/ibdlsw/tech/dls3_rg.htm
We have the following load balancing scenario:
Router A
dlsw local-peer peer-id 10.2.19.1
dlsw remote-peer 0 tcp 10.2.24.2 circuit weight 20
dlsw remote-peer 0 tcp 10.2.20.1 circuit weight 10
dlsw load-balance circuit-count
dlsw timer explorer-wait-time 100
The dlsw load-balance circuit-count defaults to 10
, giving the load balance ratio of 2:1
If have a dlsw load-balance circuit-count of 5, do we use the following
for a 4:1 ratio
dlsw remote-peer ..... circuit weight 20
dlsw remote-peer ......circuit weight 5 ??
OR
dlsw remote peer ..... circuit weight 20
dlsw remote peer ----- circuit weight (blank)??
I am confused as to whether we should leave the weight blank or fill in
a value for the second peer
Any help appreciated.
Thanks
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