From: Ram Shummoogum (rshummoo@ca.ibm.com)
Date: Sat Feb 08 2003 - 01:12:29 GMT-3
10011101.10101101.00110100.00000000-255
10010000.10100000.00111010.00000000-255
10010111.10101000.01111010.00000000-255
10011010.10100100.01101010.00000000-255
MMMMDDDD.MMMMDDMD.MDMDDDDM.DDDDDDDD
M=MATCH AND D=DON'T CARE
Considering the M first and replacing the D by 0
10010000.10100000.00100000.00000000=144.160.32.0
As far as the mask is concerned, the M becomes a 0 and the D becomes 1
00001111.00001101.01011110.11111111=15.13.94.255
HTH
Cheers,
RAM
"Tony Huang" <tonyh5@hotmail.com>@groupstudy.com on 02/07/2003 08:24:05 PM
Please respond to "Tony Huang" <tonyh5@hotmail.com>
Sent by: nobody@groupstudy.com
To: "pita40" <pita40@hotmail.com>, <ccielab@groupstudy.com>
cc:
Subject: Re: Filtering
Hi, Pita,
Can you explain how does the one rule work? Many thanks.
Cheers,
Tony
----- Original Message -----
From: "pita40" <pita40@hotmail.com>
To: <>
Sent: Saturday, February 08, 2003 10:48 AM
Subject: Filtering
> I want to filter the following routes using one access-list.
>
> 157.173.52.0
> 144.160.58.0
> 151.168.122.0
> 154.164.106.0
>
> I got 144.160.32.0 15.13.94.255
>
> Is this answer correct?
>
> Please help.
> .
.
.
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