From: Lab Candidate (labccie@xxxxxxxxx)
Date: Sun Jul 14 2002 - 02:03:18 GMT-3
Mamoor,
This is obvious, since you said the port speed is 64000 and cir is 32000,
if you want to utilized the most of your available bandwidth for burst
purpose, the be would be equal to port_speed minus cir, hence 32000 bps.
I was reading the power-session 2002, here on page 66 they have given the
values like :
Port Speed: 64000 Bps
CIR : 32000 Bps (Average Rate of Traffic Without Congestion)
Mincir: 16000 Bps (Average Rate of Traffic With Congestion)
Bc: 4000 Bps (Amount of Data Sent Per Interval)
Be: 32000 Bps (Amount of Excess Allowed Once Credit Has Built Up)
interface Serial0
ip address 10.10.10.1 255.255.255.0
encapsulation frame-relay
frame-relay traffic-shaping
frame-relay class ccie
map-class frame-relay ccie
frame-relay adaptive-shaping becn
frame-relay cir 32000
frame-relay mincir 16000
frame-relay bc 4000
frame-relay be 32000
Can someone explain why Be = 32000 , why not Be = 32000 * 0.125 = 4000
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