From: Peter (peter@xxxxxxxxx)
Date: Sun Feb 25 2001 - 11:25:28 GMT-3
I think Scott is right. The VICs fit into a WAN slot like on the NM-1E2W
and will light the amber lights but for the VICs to work, they must be
pluged into a NM-1V or NM-2V.
Peter
----- Original Message -----
From: "Scott Morris" <smorris@mentortech.com>
To: "'MASK'" <afaqk@rocketmail.com>; <ccielab@groupstudy.com>
Sent: Sunday, February 25, 2001 6:25 AM
Subject: RE: VoIP on 3640
> Watch the messages at bootup, you'll see anything about invalid module in
> slot xxx. Where do you have the VIC plugged in? NM-1V or NM-2V? Are you
> running a 'plus' version of IOS? I think (if my memory isn't failing me)
> that IP-Plus is minimum for voice.
>
> Do a "show version". Not only will you get your IOS version, but you'll
see
> exactly how many of what port you have, and you should see something about
> "voice ports".
>
> Scott
>
> -----Original Message-----
> From: nobody@groupstudy.com [mailto:nobody@groupstudy.com]On Behalf Of
> MASK
> Sent: Sunday, February 25, 2001 6:58 AM
> To: ccielab@groupstudy.com
> Subject: VoIP on 3640
>
>
> hi all,
>
>
> I've a little voip prob., actually i've installed a
> VIC-2FXS card on 3640, and loaded it with IOS image
> 12.0(4)T, but when i go into dial-peer mode, i dont
> find "port slot/unit/port#" command, and other thing
> is that LEDs on the VIC card are constantly orange!!
>
> i've 32MB(DRAM) and 8MB(flash) on my 3640, BTW , which
> IOS image feature set u need to do voip?
>
> Other problem i faced is about ebgp-multihop, what i
> observed is that when i use physical interfaces to
> configure ebgp multihoping bi-driectionaly(using not-
> directly-connected interfaces on both routers to do
> peering), neighbors never go to Estab. state, but it
> works fine in one direction, ie, when i use
> not-directly-connected on one neighbor, and a
> directly-conncted on the other, the only way i seem to
> do ebgp-multihoping both ways, is to configure ebgp
> relationship using loopback interfaces on both the
> peering routers. ie.
>
> lo-----(R1)======(R2)-----lo
>
> why it works that way?
>
> Thanks in advance,
> bbye
>
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