Re: DLSw

From: YJC (stiff.yu@xxxxxxxxxxxxxxxxxx)
Date: Tue Jan 09 2001 - 23:28:48 GMT-3


   
atif,

I think we can config two dlsw peer in r2,but don't enable SR-TLB in r2,
but not need bgroup-list,if it can solve your question.
----- Original Message -----
From: Atif Awan <atifawan@hotmail.com>
To: <atifawan@hotmail.com>; <ccielab@groupstudy.com>
Sent: Wednesday, January 10, 2001 1:33 AM
Subject: Re: DLSw

>
> I have been thinking about it and there is one thing that comes to my
mind.
> If i define two bridge groups, put ether of Router2 in one bridge group
and
> ring 1 in bridge group 2 and then define two dlsw bgroup-lists, one
> permitting bridge 1 and the other bridge 2 and map them to the remote peer
> statements of the two other routers ... will this stop Router 3 from
> communicating with the ether of Router 2 and the Ether of Router 1 from
> communicating with the ring 1 of router 2. I think it should work ..
> unfortunately i dont have the resources to test it out so if someone can
> confirm this i will be grateful.
>
> regards
> Atif
>
>
> >From: "Atif Awan" <atifawan@hotmail.com>
> >Reply-To: "Atif Awan" <atifawan@hotmail.com>
> >To: ccielab@groupstudy.com
> >Subject: DLSw
> >Date: Wed, 10 Jan 2001 01:17:58
> >
> >if you have two DLSw remote peers configured on a router that has both a
> >token ring and an ethernet interface. One of the peers has a token ring
> >interface while the other has an ethernet interface. If the requirement
is
> >that the bridging connectivity between the token rings should be
> >independent
> >from the bridging connectivity between the ethernet segments then how can
> >this be achieved ?
> >
> >Let me try to make this a little clear :
> >
> >Router 1 --------- Router2 ---------- Router 3
> > | | | |
> >ether ether ring1 ring 2
> >
> >Now if i have to configure dlsw between router1 and router 2 and then
> >router
> >2 and router 3 and such that ether of router 1 should only be able to
> >connect to the ether of router 2 and ring 1 of router 2 should be only
able
> >to connect to the ring 2 of router 3 and vice versa then how can this be
> >achieved ?
> >
> >



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