Re: how to ipv6 address aummary

thnx.that D1s so clear now

On Wed, May 12, 2010 at 5:31 PM, Maarten Vervoorn
<mr.vervoorn_at_gmail.com>wrote:

> Every hex digit between the colon is 16 bits. every hex digit is 4 bits
> Firt check the hex digits that are the same.
> 2001:150:1: = 48 bit (3x16)
> the first difference is in the next colon. Write down the complete hex
> structure.
> 0005
> 0008
> The first three hex digits are the same: 000 this 12 bits (3x4)
> Then we have left 5 and 8. write it down in binary
> 0101
> 1000
> We can see that there no bits match so your mask will be 48+12=60
>
> Regards,
>
> Maarten Vervoorn
>
>
> 2010/5/11 Mustafa Yadav <mustafa.yadav_at_gmail.com>
>
>> hi all,
>>
>>
>> I stucked about how to do a summary for ipv6 routes .
>> let s say we want to summary belows route
>> 2001:150:1:5::5/64
>> 2001:150:1:8::8.64
>>
>> can you help me a lD1D1tle to clarD1fy thD1s issue on my mind?
>>
>> thx in advance
>>
>>
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Received on Wed May 12 2010 - 23:21:03 ART