Read the following lines to calculate a summary route for a couple of IPv6
routes:
- Rewrite the routes in this form x:x:x:x:x:x:x:x, where the 'x's are
the hexadecimal values of the eight 16-bit pieces of the address.
- convert all the routes to the binary format
- determine the common bits beginning from the left.
- add necessary 0s to previous common bits in order to obtain a address
of 128 bits.
- convert this value(common bits + necessary 0s) to the hexadecimal
format.
- The length in bits of the common part is the mask of the summary route.
Hope this help,
Mohamed Ouamer
http://www.ciscocciebootcamp.com
2010/5/11 Mustafa Yadav <mustafa.yadav_at_gmail.com>
> hi all,
>
> I stucked about how to do a summary for ipv6 routes .
> let s say we want to summary belows route
> 2001:150:1:5::5/64
> 2001:150:1:8::8.64
>
> can you help me a lD1D1tle to clarD1fy thD1s issue on my mind?
>
> thx in advance
>
>
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Received on Tue May 11 2010 - 19:21:27 ART
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