Re: Redistribution

From: Ravi Singh <way2ccie_at_googlemail.com>
Date: Sat, 16 May 2009 18:11:32 +0100

Hi Anantha,

For any routing protocol to be redistributed into another, the routes
that are considered are the ones in the routing table plus the
connected interfaces on which the redistributed protocol is enabled.
For example in your case, if you are redistributing rip routes into
OSPF, the ospf process on R2 checks the following two things
1) RIP routes in the routing table..kind of running the command show
ip route rip
2) Connected interfaces where the RIP protocol is enabled which means
not all connected interfaces but only the ones which have RIP enabled
on them

While there are a lot of other points of consideration with different
protocols in redistribution , the general rule of redistribution is
the one above.

HTH,
Ravi

On Sat, May 16, 2009 at 5:42 PM, Anantha Subramanian Natarajan
<anantha.natarajan_at_gravitant.com> wrote:
> Hi All,
>
> I am trying to understand,how redistribution occurs and any help would be
> really appreciated.
>
> I have the below topology
>
>
> Fa0/1 --R1 --F0/0(10.1.1.1/30) ----- Fa0/0(10.1.1.2/30) ---R2
> -Fa0/1(172.16.2.1/24)
>
> Between R1 and R2 OSPF area0 is running.On R2 Fa0/1,ripv2 is enabled.The rip
> routes are redistributed into OSPF on R2.I can see 172.16.2.0/24 subnet on
> R1 learned through OSPF.My question is ,should not 172.16.2.0/24 should be
> in the routing table of R2 to get redistributed into OSPF,or this is not
> applicable for directly connected networks and only apply for the RIP
> learned routes ?
>
> Kindly let me know your comments.
>
> Thanks
>
> Regards
> Anantha Subramanian Natarajan
>
>
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Received on Sat May 16 2009 - 18:11:32 ART

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