From: Osamah Shaheen (ShaheenO@maaden.com.sa)
Date: Thu Sep 11 2008 - 15:48:27 ART
As my understand:
the maximum TC=125ms.
Then. Bc=CIR*Tc=128kbps*125/1000=16000bps.
The question ask for 1/4th of the rate. so bc will equual=16000/4=4000
Hope this make sense.
Sam
________________________________
From: nobody@groupstudy.com on behalf of last end
Sent: Thu 11/09/2008 08:10 AM
To: ccielab@groupstudy.com
Subject: IEWB Vol2 version4.1 Lab 1 - Task 7.2
Hi group,
Now, I really struggle with workbook.
And I can not understand how calculate bc rate on this task.
According to Solution guide, the answer is as below.
Could you lead me to this answer...
$$$$$$$$$ From Solution guide $$$$$$$$$
R1:
ip cef
!
class-map match-all ICMP
match protocol icmp
!
policy-map POLICE_ICMP
class ICMP
police cir 128000 bc 4000
!
interface FastEthernet0/0
service-policy output POLICE_ICMP
$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$
Best regards.
sal
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