From: Scott Morris (swm@emanon.com)
Date: Tue Aug 19 2008 - 11:35:43 ART
Ahhhh... 12 was the hex not the decimal in that question. Good catch for
he /58!
(I need to find the lab!)
Scott
-----Original Message-----
From: nobody@groupstudy.com [mailto:nobody@groupstudy.com] On Behalf Of
GAURAV MADAN
Sent: Tuesday, August 19, 2008 4:39 AM
To: Nitro Drops
Cc: ccielab@groupstudy.com
Subject: Re: IEWB - IPv6 Queries
Regarding ur 3rd question ..
2001:141:1:12
2001:141:1:25
12 in hex is 010010 in bia
25 in hex is 100101 in bia
Therefore 2001:141:1::0 / 58
16*3 + 10 = 58
Regarding your second question ..( although ur question is not clear to me
what u intended to ask ).... i prefer putting ipv6 map to link local of far
end ..
But if you wanna be 100 % sure ( as no marks is deducted for xtra config )
.. put 2 frame-relay map statements .. 1 for far end link local address and
other for far end actual IPV6 adderss.
HTH
GAURAV MADAN.
On Tue, Aug 19, 2008 at 12:50 PM, Nitro Drops <nitrodrops@hotmail.com>
wrote:
> Hi Folks,
>
> Need some kind advices from network experts, have tried the IE forum, but
no replies.
>
> Q1. Task 6.1 : IPv6 "eui-64"
> When configuring IPv6 addresses on the interfaces, when do i need to
include IPv6 host address "eui-64"?
> 2001:192:10:X::/64 eui-64
> In R1, "eui-64" is used on the F0/0 interface. But not on R2's F0/0
> and R5's E0/1. Is "eui-64" needed only when I need to carry out a
> static frame-relay map statement?
>
> Q2. Task 6.2 : Frame-Relay map statement on R2 Instead of using 2 x
> Frame-Relay map statements, one for the IPv6
> /64 Network and one for the Link Local /64Host, can i just use 1 x
> Frame-Relay map statement for an /128 IPv6 Network + Host instead
> frame-relay map ipv6 FE80::204:27FF:FEB5:2F60 201 frame-relay map ipv6
> 2001:141:1:12::1 201 broadcast into frame-relay map ipv6
> 2001:141:1:12:204:27FF:FEB5:2F60 201 broadcast
>
> Q3. Task 6.3 : Summarize IPv6 address
> Is the summarized mask supposed to be /59 instead of /58?
> 2 characters = 1 byte = 8 bits
> 2001:141:1:12 = 2001 (16bits) : 0141 (16bits) : 0001 (16bits) : 0012
> (00000000 0000 1100)
> 2001:141:1:25 = 2001 (16bits) : 0141 (16bits) : 0001 (16bits) : 0025
> (00000000 0001 1001) Summarised Masks = 16 + 16 + 16 + 11 = 59 bits?
> (From Left to Right) Thanks for any kind replies.
> Much appreciated.
>
> Cheers
> Nit
>
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