RE: simple query on ACL

From: Cisco Champ (cisco_champ@delhirocks.com)
Date: Thu Jul 10 2008 - 16:05:09 ART


Cool this works for me..Thanks for the help..

I tried the method sent by Joe prior to your post and Pairing picked from you
and it work for me. I'm not sure if there is any reverse engg on this to drive
the original subnets from the ACL ;-)

Appreciate your reply.

Regards,

> From: mgreenlee@ipexpert.com
> To: cisco_champ@delhirocks.com; ccielab@groupstudy.com
> Subject: RE: simple query on ACL
> Date: Thu, 10 Jul 2008 13:45:25 -0400
>
> Look at the binary for the bits. 7 of the bits are the same for each pair.
>
> 5 - 00000101
> 13 00001101
>
> 10 - 00001010
> 14 - 00001110
>
> There is a difference between a subnet mask and a wildcard mask. 0.0.4.255
> and 0.0.8.255 are wildcard masks, only stating which bits to match.
>
> Marvin Greenlee, CCIE #12237 (R&S, SP, Sec)
> Senior Technical Instructor - IPexpert, Inc.
> Telephone: +1.810.326.1444
> Fax: +1.810.454.0130
> Mailto: mgreenlee@ipexpert.com
>
> Progress or excuses, which one are you making?
>
>
>
> -----Original Message-----
> From: nobody@groupstudy.com [mailto:nobody@groupstudy.com] On Behalf Of
> Cisco Champ
> Sent: Thursday, July 10, 2008 1:32 PM
> To: ccielab@groupstudy.com
> Subject: simple query on ACL
>
> Hi:
>
> In one of the question requirement was to match (192.168.5.0, 10.0, 13.0
and
> 14.0) network. Solution is given below, which is giving the results
> correctly.
>
> access-list 1 permit 192.168.10.0 0.0.4.255
> access-list 1 permit 192.168.5.0 0.0.8.255
>
> But my question is how can we used '192.168.5.0' as Network address for
> subnet
> mask 255.255.248.0 it should be 192.168.4.0. But when I do this I didn't
get
> the required results. Can any one tell me how this one is working.
>
> Thanks in advance!!
>
>
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