From: Cisco Champ (cisco_champ@delhirocks.com)
Date: Thu Jul 10 2008 - 14:32:17 ART
Hi:
In one of the question requirement was to match (192.168.5.0, 10.0, 13.0 and
14.0) network. Solution is given below, which is giving the results
correctly.
access-list 1 permit 192.168.10.0 0.0.4.255
access-list 1 permit 192.168.5.0 0.0.8.255
But my question is how can we used '192.168.5.0' as Network address for subnet
mask 255.255.248.0 it should be 192.168.4.0. But when I do this I didn't get
the required results. Can any one tell me how this one is working.
Thanks in advance!!
This archive was generated by hypermail 2.1.4 : Mon Aug 04 2008 - 06:11:54 ART