From: Narbik Kocharians (narbikk@gmail.com)
Date: Mon May 05 2008 - 17:04:32 ART
excellent explanation, it's like the calculators, when you have, let's say
96785 multiple by 64578 and then subtract 578, you normally do the
multiplication and put the result in the memory and then recall that number
from memory and subtract 578. You are basically doing the same thing here.
On 5/5/08, Todd, Douglas M. <DTODD@partners.org> wrote:
>
> Just some thoughts and ideas for testing:
>
> ^([0-9]+)(_\1)*$
>
> \1 = backreference to what you previously matched. Is this what you wanted
> in
> the regex... and not escaping actual bracket?
>
> _ is the wild card here. Thus you could/might get away with ([0-9]+_)\1?
>
> the * might cause some issues since it's 0 or more instances, but also
> "wildcard" for anything, thus greediness kicks in.
> The ? is 0 or more instances.
>
> () can be optional if no grouping is needed or backreferencing is needed.
>
> Remove the anchors ^ $ if we need to get the as anywhere else in the
> string
> beside beginning and end. Add the anchors if you want to be very
> specific and remove the possible "greediness" of the regex.
>
>
> Just some ideas.. :)
>
> DMT
>
>
>
>
> -----Original Message-----
> From: nobody@groupstudy.com [mailto:nobody@groupstudy.com] On Behalf Of
> Narbik
> Kocharians
> Sent: Monday, May 05, 2008 12:41 AM
> To: Amir.Tahir/Wateen/Lahore
> Cc: V.Shekhar@globalassurance.net; Rakesh Hegde; ccielab@groupstudy.com
> Subject: Re: BGP regular expression
>
> It looks good but i think you menat to do ^([0-9]+)(_1\)*$. This will
> match
> prepending of the same AS.
>
> On 5/4/08, Amir.Tahir/Wateen/Lahore <Amir.Tahir@wateen.com> wrote:
> >
> > I believe if you try the following expression, it will help
> >
> > If the AS is prepended, the following expression could be used to
> > match the successive occurrences ^([0-9]+)(-\1)*$
> >
> > Do let us know yor findings and feedback
> >
> > Regards / AT
> >
> > -----Original Message-----
> > From: nobody@groupstudy.com [mailto:nobody@groupstudy.com] On Behalf
> > Of V.Shekhar@GlobalAssurance.net
> > Sent: Thursday, May 01, 2008 10:29 PM
> > To: Rakesh Hegde
> > Cc: ccielab@groupstudy.com
> > Subject: Re: BGP regular expression
> >
> > Sorry i meant to ask does it List 1.0 & 2.0 with ^(100_)+$ ?
> > -V Shekhar
> > CCIE(sec)#17589/CISSP/RHCE.
> >
> > V.Shekhar@GlobalAssurance.net wrote:
> > > Does it list 1& 4 if u use ^(100_)+$ ?
> > >
> > > -V Shekhar
> > > CCIE(sec)#17589/CISSP/RHCE.
> > >
> > > Rakesh Hegde wrote:
> > >> Guys,
> > >>
> > >> I've got the following routes in the bgp table
> > >>
> > >> 192.168.1.0 100
> > >> 192.168.2.0 100 100 100
> > >> 192.168.3.0 100 200 300
> > >>
> > >>
> > >> 1. Sh ip bgp reg (_100_)+ as expected lists all 3 networks
> > >>
> > >> 2. Sh ip bgp reg ^(_100_)+ as expected lists all 3 networks
> > >>
> > >> 3. Sh ip bgp reg (_100_)+$ as expected lists 192.168.1.0 and
> > >> 192.168.2.0
> > >>
> > >> 4. Sh ip bgp reg ^(_100_)+$ lists only 192.168.1.0 .
> > >>
> > >> Any idea why no 4 is not listing 192.168.2.0 ?
> > >>
> > >> Thanks in advance
> > >>
> > >> -Rakesh
> > >>
> > >>
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>
> --
> Narbik Kocharians
> CCSI#30832, CCIE# 12410 (R&S, SP, Security) www.Net-Workbooks.com Sr.
> Technical
> Instructor
>
>
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-- Narbik Kocharians CCSI#30832, CCIE# 12410 (R&S, SP, Security) www.Net-Workbooks.com Sr. Technical Instructor
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