From: Radioactive Frog (pbhatkoti@gmail.com)
Date: Thu Jan 03 2008 - 06:45:38 ARST
Hi guys,
Command: police 10megs 1megs conform-action transmit exceed-action drop
My understanding is in above command when we do policing, 10 megs link would
able to transmit 11 megs if bandwidth is available on the link. But I am too
much confussed by looking at the below documents with different argument:
Cisco says: 1 megs parameter won't do anything e.g. 10 megs policy rate will
be only 10 megs (it wont go to 11 megs with burst).
Juniper doc says: bursting will be additioan to the 10 megs so link would be
able to transmit 11 megs (10megs+1megs burst).
Can someone clearify this to me please....
Cisco document says about policing: " Policing Propagates bursts. Does no
smoothing."
http://www.cisco.com/en/US/docs/ios/12_0/qos/configuration/guide/qcpolts.html#wp5221
Juniper document says: "
"Policing employs the *token-bucket algorithm*, which enforces a limit on
average bandwidth while allowing bursts up to a specified maximum value. It
offers more flexibility than the *leaky bucket algorithm* (see Configure
Receive and Transmit Leaky Bucket
Properties<http://www.juniper.net/techpubs/software/junos/junos42/swconfig-interfaces42/html/interfaces-physical-config12.html#1013471>)
in regulating bursty traffic and never discards packets."
Frog
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