From: Smithson, Brandon K (brandon.k.smithson@citi.com)
Date: Wed Dec 19 2007 - 13:29:29 ART
Actually, doesn't that just filter 1,3,5 and 7?
Start ip = 1 = 00000001
Mask = 6 = 00000110
That gives possible choices of:
00000001 = 1
00000011 = 3
00000101 = 5
00000111 = 7
Since the starting IP is 1 and the mask has a 0 bit in that position,
any other filtered ip must always be an odd number.
-----Original Message-----
From: nobody@groupstudy.com [mailto:nobody@groupstudy.com] On Behalf Of
Edison Ortiz
Sent: Wednesday, December 19, 2007 9:11 AM
To: 'Lora Ganeva'; 'shiran guez'
Cc: ccielab@groupstudy.com
Subject: RE: rip networks filtering
No, that filters network 199.16.1.0-199.16.7.255 on the first ACL and
199.16.8.0-.255 on the second ACL - not just even networks.
Unless I misunderstood the requirement, that should cover it.
Edison Ortiz
Routing and Switching, CCIE # 17943
_____
From: Lora Ganeva [mailto:lganeva@mobiltel.bg]
Sent: Wednesday, December 19, 2007 9:53 AM
To: Edison Ortiz; shiran guez
Cc: ccielab@groupstudy.com
Subject: RE: rip networks filtering
This filters all even networks:-(
From: Edison Ortiz [mailto:edisonmortiz@gmail.com]
Sent: 19 dEKEMWRI 2007 G. 16:43
To: Lora Ganeva; 'shiran guez'
Cc: ccielab@groupstudy.com
Subject: RE: rip networks filtering
199.16.1.0 0.0.6.255
199.16.8.0 0.0.0.255
Edison Ortiz
Routing and Switching, CCIE # 17943
-----Original Message-----
From: nobody@groupstudy.com [mailto:nobody@groupstudy.com] On Behalf Of
Lora Ganeva
Sent: Wednesday, December 19, 2007 8:44 AM
To: shiran guez
Cc: ccielab@groupstudy.com
Subject: RE: rip networks filtering
Hi all,
But 199.16.1.0 0.0.7.255??? this is actually 199.16.0.0 0.0.7.255 and
the zero
subnet has to be filtered.
BR,
Lora
From: shiran guez [mailto:shiranp3@gmail.com]
Sent: 19 dEKEMWRI 2007 G. 15:15
To: Lora Ganeva
Subject: Re: rip networks filtering
my mistake didnt saw the range sign
Subodh given you the correct answer!
On Dec 19, 2007 2:11 PM, Lora Ganeva <lganeva@mobiltel.bg> wrote:
Hi experts,
I am experiencing some problems with the following task:
Two routers , let's say R1 and R2 are connected (media is not important,
let's say it is Ethernet)
R1 Eth1/0---------------150.1.1.0/24------------- Eth1/0 R2
R1:
Eth1/0
Ip add 150.1.1.1 <http://150.1.1.1/> 255.255.255.0
<http://255.255.255.0/>
R2:
Eth1/0
Ip add 150.1.1.2 <http://150.1.1.2/> 255.255.255.0
<http://255.255.255.0/>
Routers are running rip and R2 is advertising the following networks to
R1
199.16.0.0/24
199.16.1.0/24
199.16.2.0/24
199.16.3.0/24
199.16.4.0/24
199.16.5.0/24
199.16.6.0/24
199.16.7.0/24
199.16.8.0/24
199.16.10.0/24
199.16.11.0/24
199.16.12.0/24
199.16.13.0/24
199.16.14.0/24
199.16.15.0/24
The task requires by configuring only R1 (not interface level command)
to allow with an ACL with only 2 lines the following subnets:
199.16.1.0/24 - 199.16.8.0/24
I have though a lot of any kind of ACLs but i still haven't come to a
good solution.
Any help will be appreciated,
Thanks,
Lora
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