RE: rip networks filtering

From: Lora Ganeva (lganeva@mobiltel.bg)
Date: Wed Dec 19 2007 - 12:39:04 ART


Hi,

 

See below:

 

 

199.16.1.0 ----199.16.00000001.0

Wildcard:

 

0.0.6.255 --C 0.0.00000110.0 (0 bexact match, 1 b donb care)b&so, with this wildcard mask you say that the last bit should be always zero..(no even subnets)

 

BR,

Lora

 

 

 

From: Edison Ortiz [mailto:edisonmortiz@gmail.com]
Sent: 19 PP5P:P5P<P2QP8 2007 P3. 17:34
To: Lora Ganeva; 'shiran guez'
Cc: ccielab@groupstudy.com
Subject: RE: rip networks filtering

 

Ibm on the road. Ibll try it when I get some time and equipment to test on.

If someone else has any suggestion in the meantime, feel free to contribute.

 

Edison Ortiz

Routing and Switching, CCIE # 17943

________________________________

From: Lora Ganeva [mailto:lganeva@mobiltel.bg]
Sent: Wednesday, December 19, 2007 10:12 AM
To: Edison Ortiz; shiran guez
Cc: ccielab@groupstudy.com
Subject: RE: rip networks filtering

 

Hi, Just try it.

 

And youbll seeL

 

 

 

 

From: Edison Ortiz [mailto:edisonmortiz@gmail.com]
Sent: 19 PP5P:P5P<P2QP8 2007 P3. 17:11
To: Lora Ganeva; 'shiran guez'
Cc: ccielab@groupstudy.com
Subject: RE: rip networks filtering

 

No, that filters network 199.16.1.0-199.16.7.255 on the first ACL and 199.16.8.0-.255 on the second ACL b not just even networks.

 

Unless I misunderstood the requirement, that should cover it.

 

Edison Ortiz

Routing and Switching, CCIE # 17943

________________________________

From: Lora Ganeva [mailto:lganeva@mobiltel.bg]
Sent: Wednesday, December 19, 2007 9:53 AM
To: Edison Ortiz; shiran guez
Cc: ccielab@groupstudy.com
Subject: RE: rip networks filtering

 

This filters all even networksL

 

From: Edison Ortiz [mailto:edisonmortiz@gmail.com]
Sent: 19 PP5P:P5P<P2QP8 2007 P3. 16:43
To: Lora Ganeva; 'shiran guez'
Cc: ccielab@groupstudy.com
Subject: RE: rip networks filtering

 

199.16.1.0 0.0.6.255

199.16.8.0 0.0.0.255

 

Edison Ortiz

Routing and Switching, CCIE # 17943

-----Original Message-----
From: nobody@groupstudy.com [mailto:nobody@groupstudy.com] On Behalf Of Lora Ganeva
Sent: Wednesday, December 19, 2007 8:44 AM
To: shiran guez
Cc: ccielab@groupstudy.com
Subject: RE: rip networks filtering

 

Hi all,

 

 

 

But 199.16.1.0 0.0.7.255??? this is actually 199.16.0.0 0.0.7.255 and the zero

subnet has to be filtered.

 

 

 

BR,

 

Lora

 

 

 

From: shiran guez [mailto:shiranp3@gmail.com]

Sent: 19 dEKEMWRI 2007 G. 15:15

To: Lora Ganeva

Cc: ccielab@groupstudy.com

Subject: Re: rip networks filtering

 

 

 

my mistake didnt saw the range sign

 

 

 

Subodh given you the correct answer!

 

On Dec 19, 2007 2:11 PM, Lora Ganeva <lganeva@mobiltel.bg> wrote:

 

Hi experts,

 

 

 

I am experiencing some problems with the following task:

 

 

 

Two routers , let's say R1 and R2 are connected (media is not important,

let's say it is Ethernet)

 

 

 

R1 Eth1/0---------------150.1.1.0/24------------- Eth1/0 R2

 

 

 

R1:

 

 

 

Eth1/0

 

Ip add 150.1.1.1 <http://150.1.1.1/> 255.255.255.0 <http://255.255.255.0/>

 

 

 

R2:

 

Eth1/0

 

Ip add 150.1.1.2 <http://150.1.1.2/> 255.255.255.0 <http://255.255.255.0/>

 

 

 

Routers are running rip and R2 is advertising the following networks to

R1

 

 

 

 

 

199.16.0.0/24

 

199.16.1.0/24

 

199.16.2.0/24

 

199.16.3.0/24

 

199.16.4.0/24

 

199.16.5.0/24

 

199.16.6.0/24

 

199.16.7.0/24

 

199.16.8.0/24

 

199.16.10.0/24

 

199.16.11.0/24

 

199.16.12.0/24

 

199.16.13.0/24

 

199.16.14.0/24

 

199.16.15.0/24

 

 

 

The task requires by configuring only R1 (not interface level command)

to allow with an ACL with only 2 lines the following subnets:

 

 

 

 

 

199.16.1.0/24 - 199.16.8.0/24

 

 

 

I have though a lot of any kind of ACLs but i still haven't come to a

good solution.

 

 

 

Any help will be appreciated,

 

 

 

Thanks,

 

Lora

 



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