From: Ben (bmunyao@gmail.com)
Date: Tue Sep 18 2007 - 16:33:39 ART
Hi Joseph,
So if the task stated
2Mbps cir with the MINIMUM tc
I know minimum Tc for shaping is 10ms. Does MQC police have a similar
concept, given that its "bucket(s)" are replenished on a prorated basis, not
per Tc?
Sincerely
Ben
On 9/18/07, Joseph Brunner <joe@affirmedsystems.com> wrote:
>
> For policing its
>
> Bits |bytes for bc (which sets tc)|bytes for be
>
> For shaping its
>
> Bits |BITS for bc (which sets tc|BITS for be
>
>
> So if the task stated
>
> 2Mbps cir with the MINIMUM tc
>
> For policing its
>
> Police 2000000 2500
>
> For shaping its
>
> Shave average 2000000 20000
>
> Check this policing config of the same task
>
> !
> !
> class-map match-all http
> match protocol http
> !
> !
> policy-map httppolicy
> class http
> police 2000000 2500
> class class-default
> fair-queue
>
>
>
> interface GigabitEthernet0/0
> service-policy output httppolicy
>
> !
> !
> Verification;
>
> rack1r6#sh policy-map int g0/0
> GigabitEthernet0/0
>
> Service-policy output: httppolicy
>
> Class-map: http (match-all)
> 0 packets, 0 bytes
> 5 minute offered rate 0 bps, drop rate 0 bps
> Match: protocol http
> police:
> cir 2000000 bps, bc 2500 bytes
> conformed 0 packets, 0 bytes; actions:
> transmit
> exceeded 0 packets, 0 bytes; actions:
> drop
> conformed 0 bps, exceed 0 bps
>
> Class-map: class-default (match-any)
> 22 packets, 2254 bytes
> 5 minute offered rate 0 bps, drop rate 0 bps
> Match: any
> Queueing
> Flow Based Fair Queueing
> Maximum Number of Hashed Queues 256
> (total queued/total drops/no-buffer drops) 0/0/0
>
> Joe
>
> -----Original Message-----
> From: nobody@groupstudy.com [mailto:nobody@groupstudy.com] On Behalf Of
> Mohmmad, Imran
> Sent: Tuesday, September 18, 2007 11:23 AM
> To: ccielab@groupstudy.com
> Subject: Traffic policing
>
> Hi Experts,
>
>
>
> Plz help me I am struggling from yesterday to identify the formula for
> calculating the Bc and Be, while policing the traffic, I have also
> checked the Cisco and from earlier response of my question I got the
> following formula to calculate the Bc and I am not able to digest this
> equation, can anyone Plz explain me how to interpret the same
>
>
>
> Normal Burst = CIR [BPS] *(1 byte)/ (8 bits) *1.5 seconds
>
>
>
> -Imran
>
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