From: Usankin, Andrew (Andrew.Usankin@twtelecom.com)
Date: Thu Aug 30 2007 - 17:29:53 ART
You have to remember that in IPv6 address notation we are using
hexadecimal numbers.
12(hex) = 010010(bin)
25(hex) = 100101(bin)
So as you can see there is no common bits in this two numbers, so prefix
length would be 64-6, which is /58.
Andrew
-----Original Message-----
From: nobody@groupstudy.com [mailto:nobody@groupstudy.com] On Behalf Of
Sadiq Yakasai
Sent: Thursday, August 30, 2007 12:56 PM
To: Cisco certification
Subject: IPV6 Address Summarization
Hi Guys,
Please could someone help out a guy here:
I need to summarize these two IPV6 addresses:
2001:141:1:12::/64
2001:141:1:25::/64
I have done it many times over, and what I find to be the summarized
address is:
2001:141:1::/59
However, an excercise I am doing here says is
2001:141:1::/58
Please can someone confirm if I am right or wrong here?
Thanks!!
Sadiq
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