From: Jason Guy \(jguy\) (jguy@cisco.com)
Date: Thu Aug 30 2007 - 17:01:20 ART
Sadiq,
Remember IPv6 addresses are in HEX. So you need to break each digit
down by 4bits. So for the 0x12 and 0x25, you have:
0001 0010 = 0x12
0010 0101 - 0x25
I think you can take it from there. :)
Jason
> -----Original Message-----
> From: nobody@groupstudy.com [mailto:nobody@groupstudy.com] On Behalf
Of
> Sadiq Yakasai
> Sent: Thursday, August 30, 2007 2:56 PM
> To: Cisco certification
> Subject: IPV6 Address Summarization
>
> Hi Guys,
>
> Please could someone help out a guy here:
>
> I need to summarize these two IPV6 addresses:
> 2001:141:1:12::/64
> 2001:141:1:25::/64
>
> I have done it many times over, and what I find to be the summarized
> address is:
> 2001:141:1::/59
>
> However, an excercise I am doing here says is
> 2001:141:1::/58
>
> Please can someone confirm if I am right or wrong here?
>
> Thanks!!
>
> Sadiq
>
>
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