From: prashant sansare (prashant.sansare@gmail.com)
Date: Mon Jun 04 2007 - 08:06:44 ART
Hi
Can some one please help me to understand the ACL
Scenerio:Route filtering
R1-----se0/0-----R2
Networks on R2
201.1.1.1/24
201.1.2.1/24
201.1.3.1/24
201.1.4.1/24
201.1.5.1/24
EIgrp is the routing protocol running R1 needs to receive the routers with
201.1.x.0 range that have even number in the third octet
can some one pls explain me how do we filter the third octet evn
numbers,please explain me the logic of filter the even numbers
i know how acl works and stuff and how to do router filtering
access-list 2 deny 201.1.1.0 0.0.254.255
access-list 2 permit any
router eigrp 123
network 201.1.1.0
network 201.1.2.0
network 201.1.3.0
network 201.1.4.0
network 201.1.5.0
network 201.1.6.0
distribute-list 2 out se 0/0
can any one please me explain me the logic of filtring the even from the acl
how to play with wild card mask to acheive our requirment
Regards
Prashant
This archive was generated by hypermail 2.1.4 : Sun Jul 01 2007 - 17:24:46 ART