From: Salman Abbas (dukelondon@gmail.com)
Date: Thu Nov 23 2006 - 10:20:47 ART
Hi Alexei,
Thanks for the reply. Just to confirm whether I've correctly understood u or
not, Lets say the question says: maximum is 256kbps and normal is 64Kbps,
would that mean that I'll do
Normal bytes = 256k - 64k = 192k => to bytes 24000, so the police command
would be
police 64000 24000 exceed action drop
Regards,
Salman
On 11/23/06, Alexei Monastyrnyi <alexeim@orcsoftware.com> wrote:
>
> Hi.
>
> If I understand it right from DocCD, normal burst is what you have above
> the police rate. 256k-128k=128k => to bytes 16000/ If it should be
> considered together with police rate, then just 256k=>32000 bytes. In
> either case police rate should be 128000, not 256000 IMO.
>
> I would go for
> police 128000 16000 exceed action drop
>
> HTH
> a.
>
> Salman Abbas wrote:
> > Hi guys,
> >
> > Pls help to answer the following question:
> >
> >
> > On SW1 int fa0/6, limit all UDP traffic by maximum 256Kbps and normal
> > 128Kbps to avoid congestion on your VLAN.
> >
> >
> > My solution is:
> >
> > mls qos
> > access-list 101 permit udp any any
> >
> > class-map LIMIT
> > match access-group 101
> >
> > policy-map POLICE
> > class LIMIT
> > police 256000 _____ exceed action drop
> >
> > int fa0/6
> > service-policy input POLICE
> >
> > Now the part that I dont understand is that second value in the police
> > command which is "Burst in bytes". How can I calculate it based on the
> > question above? Also, am I missing anyting else in my configuration?
> >
> >
> > Thanks in advance,
> >
> > Cheers!!!
> >
> > Salman
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