From: Edouard Zorrilla (ezorrilla@tsf.com.pe)
Date: Mon Oct 23 2006 - 01:30:01 ART
Sir Bee,
Why did you put this line:
ACL inside
deny tcp host R1_Lo host R2_Lo eq 179
?
Thanks
----- Original Message -----
From: "WorkerBee" <ciscobee@gmail.com>
To: "emmanuel daniel" <emmanueldan@gmail.com>
Cc: <ccielab@groupstudy.com>
Sent: Sunday, October 22, 2006 11:05 PM
Subject: Re: bgp problem
> You can force R2 to initial the BGP peering by applying ACL to the PIX
> interfaces:
>
> ACL inside
> deny tcp host R1_Lo host R2_Lo eq 179
>
> ACL outside
> permit tcp host R2_Lo host R1_Lo eq 179
>
> Hence, the ACL will force the peering R1 (179) <--------> R2 (High Port).
>
>
>
> On 10/23/06, emmanuel daniel <emmanueldan@gmail.com> wrote:
>> Hi
>>
>> I took my sec exam last week and i couldnt pass mainly i got less points
>> in
>> bgp. i Wantt to know where i screwed up can any one help me out here is
>> my
>> problem the qustion was some what similar to this
>>
>>
>> R1 e0/0 183.1.123.1 -------- (inside 183.1.123.10) pix (outside
>> 183.1.124.10
>> )---------183.1.124.2 e0/0 r2
>> lo 150.100.1.1
>> lo
>> 150.100.2.2
>> (BGP AS
>> 54)
>> (BGP AS 55)
>>
>> the question is r1 which is bgp as 54 wants make an ebgp peering with r2
>> with is in as 55. using thee loopbacks and make the peering such that r1
>> always uses a foreign port of 179. i thought its given just to confuse
>> me
>> and i didnt solve it bec default bgp port is 179.
>>
>>
>> Regards
>> Emmanuel.
>>
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