From: Edouard Zorrilla (ezorrilla@tsf.com.pe)
Date: Mon Oct 23 2006 - 01:25:32 ART
Sir, I do not understand very good what you mean but if you want R1 and R2
can talk thru bgp using Lo0's AFAIK, you have to make sure the Lo - R1 can
go as it is to R2, for instance nat 0 or static (inside,outside) 183.1.123.1
183.1.123.1. Finally "neighbor <IP> update-source Loopback0", after that
making the access-list outside so that the tcp 179 can hit from R2 to R1.
Some one tell me if I am wrong.
Thanks
----- Original Message -----
From: "emmanuel daniel" <emmanueldan@gmail.com>
To: <ccielab@groupstudy.com>
Sent: Sunday, October 22, 2006 10:58 PM
Subject: bgp problem
> Hi
>
> I took my sec exam last week and i couldnt pass mainly i got less points
> in
> bgp. i Wantt to know where i screwed up can any one help me out here is my
> problem the qustion was some what similar to this
>
>
> R1 e0/0 183.1.123.1 -------- (inside 183.1.123.10) pix (outside
> 183.1.124.10
> )---------183.1.124.2 e0/0 r2
> lo 150.100.1.1
> lo
> 150.100.2.2
> (BGP AS
> 54)
> (BGP AS 55)
>
> the question is r1 which is bgp as 54 wants make an ebgp peering with r2
> with is in as 55. using thee loopbacks and make the peering such that r1
> always uses a foreign port of 179. i thought its given just to confuse
> me
> and i didnt solve it bec default bgp port is 179.
>
>
> Regards
> Emmanuel.
>
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