From: Scott Morris (swm@emanon.com)
Date: Sat Jul 01 2006 - 14:59:00 ART
You'll end up with extra matches there. With a mask of .6 in the first
octet, you will match on 1,3,5,7 (and it will rewrite it to 51.1.0.1 and
51.1.0.9)
.6 is 00000110, so those two bits not caring about what values are used,
substitute 00, 01, 10 and 11 back in to see your matches.
HTH,
Scott Morris, CCIE4 (R&S/ISP-Dial/Security/Service Provider) #4713, JNCIE
#153, CISSP, et al.
CCSI/JNCI
IPExpert CCIE Program Manager
IPExpert Sr. Technical Instructor
smorris@ipexpert.com
http://www.ipexpert.com
-----Original Message-----
From: nobody@groupstudy.com [mailto:nobody@groupstudy.com] On Behalf Of
ELDHO PAUL
Sent: Saturday, July 01, 2006 6:56 AM
To: Sami
Cc: ccielab@groupstudy.com
Subject: Re: Access list
I think we can match it with 2 access lists
51.3.0.1 0.6.0.0
51.3.0.9 0.6.0.0
On 7/1/06, Sami <sy1977@gmail.com> wrote:
>
> Group,
>
> One of the task say use minimum amount of line necessary to comple
> this task.
>
> 51.3.0.1
> 51.5.0.1
> 51.7.0.1
> 51.3.0.9
> 51.5.0.9
> 51.7.0.9
>
> How can I combine in one access list ?
>
> Thanks
>
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