From: Schulz, Dave (DSchulz@dpsciences.com)
Date: Wed Apr 19 2006 - 08:45:38 GMT-3
Shamin -
Just a thought on this one....but, you may be over thinking the question
a bit. It appears that there are 3 DLCIs on the same circuit and they
are saying the 204 uses 128k, and the remaining two DLCIs share what is
left over (384k). I would interpret this as meaning just that (384k) if
this is a multipoint configuration. Or, 192k each, if they are
point-to-point circuits. The bandwidth used for protocols does not come
into the picture with frame-relay traffic shaping. HTH.
Dave Schulz,
Email: dschulz@dpsciences.com
-----Original Message-----
From: nobody@groupstudy.com [mailto:nobody@groupstudy.com] On Behalf Of
Mohammed Shameen Abdul Jabbar
Sent: Wednesday, April 19, 2006 5:30 AM
To: Cisco certification
Subject: Frame relay Traffic shapping
Hi,
I have a question on the frame-relay traffic shapping.
If in the question, it is mentioned that the port speed of s0/0 is 512K
&
DLCI 204 uses 128k, The remaining two DLCI's 201 and 203 share the "
remaining-bandwidth".
I am confused on the term "remaining-bandwidth" . I have read that ,
only
75% of the port banwidth is used for normal traffic.
So the remaining bandwith should be calculated as :
512 x 75/100 =
384kbps
DLCI 204 =
128kbps
DLCI 201 = DLCI
203 =
(384 - 128)/2 = 256/2 = 128kbps
OR is it calculated as
DLCI 204 =
128Kbps
DLCI 201 = DLCI
203 =
(512 - 128)/2 = 192Kbps
Can anyone tell me which one is the correct method.
Regards
shamin
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