RE: IE lab 9 / lab 11 -----Task-8 [ Be calc ? ]

From: xprtofnet (xprtofnet@yahoo.com)
Date: Tue Jan 31 2006 - 18:37:18 GMT-3


Thanks for the response Brian.

Be = (AR-CIR) * Tc/1000 = 234880 [for Lab 9 Be value]

Be= (7500000-160000) * 0.032 = 234880

Solutions says Be=80000 which comes if you do the
multiplication first and subtraction later....is the
solution of lab 9 task 8 Be value not correct ?

Thank you again,

--- Brian McGahan <bmcgahan@internetworkexpert.com>
wrote:

> Your order of operations are incorrect. The formula
> should be Bc = CIR
> * Tc/1000 and Be = (AR-CIR) * Tc/1000
>
>
> HTH,
>
> Brian McGahan, CCIE #8593
> bmcgahan@internetworkexpert.com
>
> Internetwork Expert, Inc.
> http://www.InternetworkExpert.com
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>
> > -----Original Message-----
> > From: nobody@groupstudy.com
> [mailto:nobody@groupstudy.com] On Behalf
> Of
> > xprtofnet
> > Sent: Tuesday, January 31, 2006 12:15 PM
> > To: ccielab@groupstudy.com
> > Cc: xprtofnet@yahoo.com
> > Subject: IE lab 9 / lab 11 -----Task-8 [ Be calc ?
> ]
> >
> > Hello,
> >
> > I am going thru the QoS excercises and am kind a
> > confused on task 8.3 of Lab 9. I think the lab 11
> task
> > 8.2 is similar to this one but the answers are
> > different based on the formula/calculation:
> >
> > e.g. in task 8.3 of lab 9 the formula used do
> > calculate Be is i believe the following:
> > Be= Tc x AR - CiR [so we do Tc x AR first and then
> > subtract it with Cir]. This give the right answer
> > according to the solution which is 80000
> >
> > Doing similar calculation for lab 11 the answer
> does
> > not correspond to the solution unless you do the
> > following:
> > Be= Tc x (AR-Cir) [do the subtraction first and
> then
> > the multiplication]
> >
> > I do not see the difference of requirement in the
> two
> > labs or am i missing any thing ?
> > Is there an an error in the solution of lab 9 task
> 8.3
> > but there is a post by Brian verifying the
> > calculation.
> >
> > Can some one shed some light on this please...is
> Be
> > calculation in lab 9 correct by doing Be= Tc x AR
> -
> > CiR [so we do Tc x AR first and then subtract it
> with
> > Cir] ?
> >
> > Thank You,
> >
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>



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