From: Nick (seajay76@nate.com)
Date: Wed Jan 11 2006 - 10:48:38 GMT-3
Please disregard the last strange mail.
(1) With the priority-queue out, the 4th queue of the interface becomes the expedite queue.
int fa0/4
priority-queue out
(2) you need to put the COS-3 packet int eh 4th queue
int fa0/4
wrr-queue cos-map 4 3 (they are the queue number and the CoS in order)
(3) Then you can use the other remaining 3 queues.
(4) Allocate the designated bandwidth to the queues.
int fa0/4
wrr-queue bandwidth 4 6 5 5
Here 4 means 4/(4+6+5+5) , 6 means 6/(4+6+5+5) , 5 means 5/(4+6+5+5)
So you might put it this way.
int fa0/4
wrr-queue bandwidth 20 30 25 25
(5) Since you allocate the bandwidth to the queues,
just put the CoSed packets in each queue
You did it for the fourth queue already in (2)
int fa0/4
wrr-queue cos-map 1 6 7
wrr-queue cos-map 2 0 1 2
wrr-queue cos-map 3 4 5
HTH~~
Regards,
Nick
----- Original Message -----
From: <Bill.McKenzie@bisys.com>
To: <ccielab@groupstudy.com>
Sent: Wednesday, January 11, 2006 10:17 PM
Subject: wrr-queue bandwidth command
> Here is the requirement :
> Cos-3 must be sent of everything else and match the following cos values to
> according bandwidth.
>
> Cos 3 = 25%
> CoS 6,7 = 20%
> CoS 0,1,2 = 30%
> CoS 4,5 = 25%
>
> Here is the solution:
>
> wrr-queue bandwidth 4 6 5 5
> wrr-queue cos-map 1 6 7
> wrr-queue cos-map 2 0 1 2
> wrr-queue cos-map 3 4 5
> wrr-queue cos-map 4 3
> priority-queue out
>
>
> I don't understand the values in the wrr-queue bandwidth command and trying
> to look at the doc cd is just confusing me more. Can anyone point me to a
> better explanation of how the values were estimated?
>
> Thanks,
> Bill
>
>
>
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