From: Ed Lui (edwlui@gmail.com)
Date: Fri Nov 25 2005 - 21:40:12 GMT-3
Grabler, Ross,
I think it should be like this "access-list 1 deny 200.0.1.10 0.0.2.8"
Also, I come up with another one. Would any one check that for me, please ?
access-list 1 permit 200.0.1.10 0.0.2.8
access-list 1 permit 200.0.1.18 0.0.2.0
access-list 1 permit 200.0.1.26 0.0.2.0
Thanks,
Ed Lui
On 11/25/05, Grabler, Ross (IT) <Ross.Grabler@morganstanley.com> wrote:
> Hi, I am trying to understand solution to the below problem
>
> Permit below in the minimal amount of lines in an acl, solution is
> below, I don't understand wildcard of 8, can someone explain? (this is
> from IE lab 17.
>
> 200.0.1.2
> 200.0.3.2
> 200.0.3.10
> 200.0.1.18
> 200.0.3.26
> 200.0.1.10
> 200.0.3.18
> 200.0.1.26
>
>
> solution
>
> access-list 1 deny 200.0.1.2 0.0.2.8
>
> access-list 1 deny 200.0.1.18 0.0.2.0
>
> access-list 1 deny 200.0.1.26 0.0.2.0
>
> access-list 1 permit any
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