From: Scott Morris (swm@emanon.com)
Date: Thu Oct 13 2005 - 07:53:18 GMT-3
But you haven't used "router (?)" on the spokes at all. :)
-----Original Message-----
From: nobody@groupstudy.com [mailto:nobody@groupstudy.com] On Behalf Of
simon hart
Sent: Thursday, October 13, 2005 4:28 AM
To: De Witt, Duane; Arun Arumuganainar; Javier Tomi
Cc: Cisco certification
Subject: RE: Router with out any routing Protocol
Duane,
Agreed on this point. But it could be argued, and this is where semantics
plays a part here, that by virtue of the fact R1 is advertising reachability
via CDP (not deliberately granted), that a routing protocol is at play
between the two devices.
Simon
-----Original Message-----
From: nobody@groupstudy.com [mailto:nobody@groupstudy.com]On Behalf Of De
Witt, Duane
Sent: 13 October 2005 09:22
To: simon hart; Arun Arumuganainar; Javier Tomi
Cc: Cisco certification
Subject: RE: Router with out any routing Protocol
Let's clear something up here: if there is a requirement to run a router
without a routing protocol it means you are required to specify "no ip
routing" on the device.
If you knew how ODR worked it would be clear that any spoke in ODR runs
without ip routing while only the hub requires ip routing to be enabled.
This is clearly documented on the docCD.
-----Original Message-----
From: simon hart [mailto:simon@harttel.com]
Sent: 13 October 2005 10:16 AM
To: Arun Arumuganainar; De Witt, Duane; Javier Tomi
Cc: Cisco certification
Subject: RE: Router with out any routing Protocol
Arun,
But that was not the question. You are putting a lot of what if's into the
equation. If there is a requirement to ping the loopbacks of R1 from R2 and
R3, then there will be need to advertise the loopbacks of R1 or the creation
of a default route pointing to R1. If R1 is going to advertise the
loopbacks then ODR would work, but ODR, although using CDP, can be classed
as a routing protocol, it is the dissemination of routing information.
Simon
-----Original Message-----
From: nobody@groupstudy.com [mailto:nobody@groupstudy.com]On Behalf Of Arun
Arumuganainar
Sent: 13 October 2005 09:07
To: simon hart; De Witt, Duane; Javier Tomi
Cc: Cisco certification
Subject: Re: Router with out any routing Protocol
Does R1 has any loop back address assigned to it !!!
If so Does any to any connectivity requirement mandated ping from R2 and R3
to R1's loop back ???
If answer to other two question is Yes . Default gateway solution will not
work !!!!
Thanks and Regards
Arun
----- Original Message -----
From: "simon hart" <simon@harttel.com>
To: "De Witt, Duane" <duane.dewitt@siemens.com>; "Javier Tomi" <fjtm@tid.es>
Cc: "Cisco certification" <ccielab@groupstudy.com>
Sent: Thursday, October 13, 2005 1:17 PM
Subject: RE: Router with out any routing Protocol
> I am not sure why you are all looking into things like LAM & ODR etc
> to accomplish what is a relatively simple task.
>
> The original question was the R1 does not run any routing protocol but
> to have connectivity to all of R3.
>
> With such a question look for the obvious first. R1 must behave like
> a host, such as PC. PC's do not run routing protocols but should be
> able to ping everything within it's associated network, it does this
> without
LAM/ODR
> etc etc. So how does a PC gain this connectivity, well it has a
> default gateway, that is an associated device that will find the path
> for it (AKA router).
>
> So we need to make R1 behave like a PC. Simple turn off ip routing
>
> no ip routing
>
> As soon as that command is entered the router will never ever run a
routing
> protocol.
>
> Okay now how to packets get out of the router, easy:-
>
> ip default-gateway R2's IP address.
>
> This is really the only answer that is being looked for. Looking into
> anything else is playing with semantics and rather confusing, and I am
sure
> does not help with learning
>
> HTH
>
> Simon
>
> -----Original Message-----
> From: nobody@groupstudy.com [mailto:nobody@groupstudy.com]On Behalf Of
> De Witt, Duane
> Sent: 13 October 2005 08:07
> To: Javier Tomi
> Cc: Cisco certification
> Subject: RE: Router with out any routing Protocol
>
>
> Hi
>
> I think it would be best to do things in steps here. I'm not disputing
> how LAM works here, but we need layer 3 connectivity with some sort of
> routing running between R1 and R2 before we can even start thinking
> about LAM. If
R1
> and R2 are in different subnets we have a straight forward layer 3
> problem which needs to be resolved before adding complex things like
> LAM on top of it.
>
> -----Original Message-----
> From: nobody@groupstudy.com [mailto:nobody@groupstudy.com] On Behalf
> Of Javier Tomi
> Sent: 13 October 2005 08:43 AM
> Cc: 'Cisco certification'
> Subject: Re: Router with out any routing Protocol
>
> Correct me if I am wrong, but with LAM There is no need of both
> routers to be on the same network. R2 will install a host route to the
> IP address of R1, and due to proxy-arp configured on R2, it will
> response to ARP request from R1 searching his default gateway. Of
> course, R2 will need a route to R1 network by some means.... Isn't it?
>
>
>
>
> Victor Cappuccio wrote:
>
> >OK, Thanks in advanced.. Any other comments
> >
> >
> >De Witt, Duane wrote:
> >
> >
> >
> >>No, R2 will still be looking for something in it's own subnet as far
> >>as I know. I'll lab it up later and check, just busy with IEWB at
> >>the moment.
> >>
> >>
> >>
> >>--------------------------------------------------------------------
> >>----
> >>
> >>*From:* Victor Cappuccio [mailto:cvictor@protokolgroup.com]
> >>*Sent:* 13 October 2005 08:28 AM
> >>*To:* De Witt, Duane
> >>*Cc:* Cisco certification
> >>*Subject:* Re: Router with out any routing Protocol
> >>
> >>
> >>
> >>Hello Duane, Many Thanks for your replys, maybe I'm saying
> >>something stupid here, but R1 haves a 10.0.0.1 /8 as a secondary
address..
> >>And by adding this I will cover all subnets, right?
> >>
> >>Thanks again
> >>Victor.
> >>
> >>
> >>
> >>De Witt, Duane wrote:
> >>
> >>R1 and R2 aren't in a common subnet, so I'm not sure what you are
> >>trying to achieve?
> >>
> >>
> >>
> >>--------------------------------------------------------------------
> >>----
> >>
> >>*From:* Victor Cappuccio [mailto:cvictor@protokolgroup.com]
> >>*Sent:* 13 October 2005 08:19 AM
> >>*To:* De Witt, Duane
> >>*Cc:* Cisco certification
> >>*Subject:* Re: Router with out any routing Protocol
> >>
> >>
> >>
> >>I wish to have a CCIE rack to play but for now, I just have a 3640
> >>gift from a good Friend... (I know that only with one router would
> >>not let me understand anything but it's cool to check weird
> >>configurations or command parameters / Do someone from the other
> >>side of the world (My time zone is GMT -4) have a rack that does not
uses
> >>in the night and be so generous to share it? :-) )
> >>
> >>R1:
> >>interface FastEthernet0/0
> >> ip address 10.0.0.1 255.0.0.0 secondary ! Thats why I told about to
> >>create a secondary address - I did not finish the idea when I sent
> >>the email / I Think I'm getting Crazy with all this stuffs.. Sorry
> >>for that ip address 10.50.50.2 255.255.255.248 speed 100
> >>full-duplex
> >>
> >>R2:
> >>interface FastEthernet4/0
> >> ip address 10.60.60.1 255.255.255.248 ip mobile arp access-group 2
> >>duplex full
> >>
> >>
> >>access-list 2 permit 10.50.50.2
> >>
> >>De Witt, Duane wrote:
> >>
> >>I don't think this scenario would work. LAM would require R1 and R2
> >>
> >>ethernet to be in the same subnet, however it will allow users on R1
> >>
> >>ethernet to be on a subnet allocate somewhere else in the network.
> >>
> >>
> >>
> >>If R1 and R2 ethernet are in different subnets how will you get
> >>
> >>communication going between the two?
> >>
> >>
> >>
> >>-----Original Message-----
> >>
> >>From: nobody@groupstudy.com <mailto:nobody@groupstudy.com>
> [mailto:nobody@groupstudy.com] On Behalf Of
> >>
> >>Victor Cappuccio
> >>
> >>Sent: 13 October 2005 07:50 AM
> >>
> >>Cc: Cisco certification
> >>
> >>Subject: Re: Router with out any routing Protocol
> >>
> >>
> >>
> >>Ok this one was easy, lets change the Scenario a little bit, using
> >>the
> >>
> >>same same topology, but now R1 is in a different Subnet than R2, so
> >>now
> >>
> >>we need to configure LAM on R2, and Redistributing the mobile into
> >>the
> >>
> >>ospf gives R3 the way to get to R1, but what about the return
> >>traffic R1
> >>
> >>
> >>
> >>-> R3?
> >>
> >>
> >>
> >>Thanks
> >>
> >>Victor.
> >>
> >>
> >>
> >>
> >>
> >>
> >>
> >>
> >>
> >>manoj menon wrote:
> >>
> >>
> >>
> >>
> >>
> >>
> >>
> >>>On R1#
> >>>
> >>>
> >>>
> >>>no ip routing
> >>>
> >>>!
> >>>
> >>>ip default-gateway <R2-E0-IP_ADD>
> >>>
> >>>!
> >>>
> >>>Either you can advertise the R1-R2 Ethernet subnet in OSPF, or
> >>>
> >>>redistribute, or static route back to R1, and redistribute static
> >>>into
> >>>
> >>>
> >>>
> >>>
> >>>
> >>
> >>
> >>
> >>
> >>>OSPF...
> >>>
> >>>
> >>>
> >>>Comments...
> >>>
> >>>
> >>>
> >>>Regards,
> >>>
> >>>Mnaoj
> >>>
> >>>
> >>>
> >>>*/Victor Cappuccio <cvictor@protokolgroup.com>
> <mailto:cvictor@protokolgroup.com>/* wrote:
> >>>
> >>>
> >>>
> >>> Hello People, consider this Scenario
> >>>
> >>>
> >>>
> >>> 10.1.1.0/24
> >>>
> >>> R1 --- Ethernet --- R2 | Network Cloud Running OSPF | R3.
> >>>
> >>> ---Vlan 50 ----
> >>>
> >>>
> >>>
> >>> You are not allowed to configure any routing protocol on R1, but
> >>>
> >>> one of
> >>>
> >>> the requirements is that R1 should be able to ping any ip
> >>> address
> >>>
> >>> in R3,
> >>>
> >>> how would you accomplish this? I thought to create a secondary
> >>>
> >>> address
> >>>
> >>> in R1 with an IP Classful Address Mask (10.0.0.1/8) and complete
> >>>
> >>> the ARP
> >>>
> >>> Table for R3 physical interfaces with R2 Ethernet Mac Address
> >>>
> >>> (since R2
> >>>
> >>> knows the complete network).- I Think this could work Ok / Have
> >>>
> >>>
> >>>
> >>>
> >>>
> >>not
> >>
> >>
> >>
> >>
> >>
> >>> tested yet .. Can you see another was of accomplishing this task?
> >>>
> >>>
> >>>
> >>>
> >>>
> >>> Regards
> >>>
> >>> Victor.
> >>>
> >>>
> >>>
> >>>
> >>>
> >>>
> >>>
> >>>
> >>>
> >>____________________________________________________________________
> >>___
> >>
> >>
> >>
> >>
> >>
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> >>>
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> >>>
> >>>
> >>>
> >>>
> >>>
> >>>
> >>>
> >>>
> >>>
> >>--------------------------------------------------------------------
> >>----
> >>
> >>
> >>
> >>
> >>
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> >>
> >>
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> >>
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> >>
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> >
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