RE: Router with out any routing Protocol

From: Scott Morris (swm@emanon.com)
Date: Thu Oct 13 2005 - 07:50:37 GMT-3


With LAM, they don't have to be in a common subnet, that's the beauty of
being able to wander around with an IP that doesn't belong someplace!
However, R2 would also need "router mobile" and would then redistribute
mobile (the /32's learned) into whatever the IGP was.

With R1, the secondary address wouldn't accomplish anything at all. Things
will be sourced from the primary address although the second appears
reachable. LAM is designed for devices that have a "way out" using their
gateway. A router with multiple networks would need a routing protocol to
tell them this.

Scott
 

-----Original Message-----
From: nobody@groupstudy.com [mailto:nobody@groupstudy.com] On Behalf Of De
Witt, Duane
Sent: Thursday, October 13, 2005 2:23 AM
To: Victor Cappuccio
Cc: Cisco certification
Subject: RE: Router with out any routing Protocol

R1 and R2 aren't in a common subnet, so I'm not sure what you are trying to
achieve?

________________________________

From: Victor Cappuccio [mailto:cvictor@protokolgroup.com]
Sent: 13 October 2005 08:19 AM
To: De Witt, Duane
Cc: Cisco certification
Subject: Re: Router with out any routing Protocol

I wish to have a CCIE rack to play but for now, I just have a 3640 gift from
a good Friend... (I know that only with one router would not let me
understand anything but it's cool to check weird configurations or command
parameters / Do someone from the other side of the world (My time zone is
GMT -4) have a rack that does not uses in the night and be
so generous to share it? :-) )

R1:
interface FastEthernet0/0
 ip address 10.0.0.1 255.0.0.0 secondary ! Thats why I told about to create
a secondary address - I did not finish the idea when I sent the email / I
Think I'm getting Crazy with all this stuffs.. Sorry for that ip address
10.50.50.2 255.255.255.248 speed 100 full-duplex

R2:
interface FastEthernet4/0
 ip address 10.60.60.1 255.255.255.248
 ip mobile arp access-group 2
 duplex full

access-list 2 permit 10.50.50.2

De Witt, Duane wrote:

I don't think this scenario would work. LAM would require R1 and R2 ethernet
to be in the same subnet, however it will allow users on R1 ethernet to be
on a subnet allocate somewhere else in the network.

If R1 and R2 ethernet are in different subnets how will you get
communication going between the two?

-----Original Message-----
From: nobody@groupstudy.com [mailto:nobody@groupstudy.com] On Behalf Of
Victor Cappuccio
Sent: 13 October 2005 07:50 AM
Cc: Cisco certification
Subject: Re: Router with out any routing Protocol

Ok this one was easy, lets change the Scenario a little bit, using the same
same topology, but now R1 is in a different Subnet than R2, so now we need
to configure LAM on R2, and Redistributing the mobile into the ospf gives
R3 the way to get to R1, but what about the return traffic R1

-> R3?

Thanks
Victor.

manoj menon wrote:

        On R1#

        no ip routing
        !
        ip default-gateway <R2-E0-IP_ADD>
        !
        Either you can advertise the R1-R2 Ethernet subnet in OSPF, or
        redistribute, or static route back to R1, and redistribute static
into

        OSPF...

        Comments...

        Regards,
        Mnaoj

        */Victor Cappuccio <cvictor@protokolgroup.com>
<mailto:cvictor@protokolgroup.com> /* wrote:

            Hello People, consider this Scenario

            10.1.1.0/24
            R1 --- Ethernet --- R2 | Network Cloud Running OSPF | R3.
            ---Vlan 50 ----

            You are not allowed to configure any routing protocol on R1, but
            one of
            the requirements is that R1 should be able to ping any ip
address
            in R3,
            how would you accomplish this? I thought to create a secondary
            address
            in R1 with an IP Classful Address Mask (10.0.0.1/8) and complete
            the ARP
            Table for R3 physical interfaces with R2 Ethernet Mac Address
            (since R2
            knows the complete network).- I Think this could work Ok / Have

not

            tested yet .. Can you see another was of accomplishing this
task?

            Regards
            Victor.



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