From: Ed Lui (edwlui@gmail.com)
Date: Sat May 14 2005 - 02:44:53 GMT-3
k c,
It will look like this. Your question is ?
--------------------------------(s0)(phy int)R4
/ 172.16.14.X
(s0.14)ptp
R1(s0.123)multipoint=========================(S0)(phy int)R2
\ 172.16.123.X
========================(s0)(phy int)R3
HTH,
On 5/13/05, k c <jwongccie@yahoo.com.hk> wrote:
> Hi Group,
>
> R1 (172.16.123.1/172.16.14.1), R2 (172.16.123.2), R3 (172.16.123.3), R4 (172.16.14.4).
> R1 is Hub, R2 & R3 are spokes within 172.16.123.0 subnet.
> "One and only one router must configured with two and only two logical FR interfaces. The three remaining routers with FR interfaces must use physical interfaces only. The logical interfaces must be of a different type"
>
> Obviously, R1 will be configured with one mp (connect to R2 and R3) and one p2p connect to R4, however, R2-R4 should be physical interfaces. Any hints?
>
> Thanks.
>
> ---------------------------------
> 7Q'Y.I&,(l7s email 3q*>!H
> $U8| Yahoo! Messenger
> http://messenger.yahoo.com.hk
>
> _______________________________________________________________________
> Subscription information may be found at:
> http://www.groupstudy.com/list/CCIELab.html
This archive was generated by hypermail 2.1.4 : Fri Jun 03 2005 - 10:11:58 GMT-3