From: Brian Dennis (bdennis@internetworkexpert.com)
Date: Wed Dec 08 2004 - 16:31:13 GMT-3
Sean,
Just take a second (1000ms) and divide it by 10 since you want
1/10th of a second. 1/10th of 1000 is 100.
Brian Dennis, CCIE #2210 (R&S/ISP-Dial/Security)
bdennis@internetworkexpert.com
Internetwork Expert, Inc.
http://www.InternetworkExpert.com
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Direct: 775-745-6404 (Outside the US and Canada)
-----Original Message-----
From: nobody@groupstudy.com [mailto:nobody@groupstudy.com] On Behalf Of
Sean C
Sent: Wednesday, December 08, 2004 10:53 AM
To: ccielab@groupstudy.com
Subject: Re: CIR=0 and Tc=?
Thanks Brian,
I should probably elaborate, I'm not setting CIR as 0 in my map-class,
just
that the task states that my CIR by the carrier is 0.
Given that my CIR is 0 by the carrier, and I'm required to set my Tc
with
the task stating that the time interval is equal to 1/10 of a second,
will
my frame-relay tc be equal to 100 or 10?
Like I wrote, my brain is just going to mush a few days before the lab.
Thanks, Sean
----- Original Message -----
From: "Brian McGahan" <bmcgahan@internetworkexpert.com>
To: "Sean C" <Upp_and_Upp@hotmail.com>; <ccielab@groupstudy.com>
Sent: Wednesday, December 08, 2004 1:03 PM
Subject: RE: CIR=0 and Tc=?
Sean,
Your CIR cannot be zero in the FRTS algorithm. You can have a
guaranteed rate of zero by the Frame Relay provider, but having a 0 CIR
in the calculation means that you send no traffic.
Brian McGahan, CCIE #8593
bmcgahan@internetworkexpert.com
Internetwork Expert, Inc.
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> -----Original Message-----
> From: nobody@groupstudy.com [mailto:nobody@groupstudy.com] On Behalf
Of
> Sean C
> Sent: Wednesday, December 08, 2004 11:28 AM
> To: ccielab@groupstudy.com
> Subject: CIR=0 and Tc=?
>
> Hello,
>
> If I'm given a CIR=0 and the time interval is 1/10 of a second, what
will
> be
> my Tc?
>
> Will I configure:
> frame-relay tc 100
> or
> frame-relay tc 10
>
>
http://www.cisco.com/univercd/cc/td/doc/product/software/ios122/122cgcr/
fw
> an_
> r/frcmds/wrffr3.htm#wp1029690
>
> My mind is going to mush with milliseconds.
>
> Thanks in advance, Sean
>
>
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