From: James (james@towardex.com)
Date: Mon Jul 19 2004 - 11:27:32 GMT-3
Hi group,
Got a question about redist'ing between protocols.
It is my understanding that when redistributing between two protocols directly,
it does not perform the exchange through the specific protocol databases, but
rather performed by going through the RIB, which you can see by issuing
'sh ip route' command.
So.. let's take an example
R1--R2--<OSPF>-----------R5--------------<EIGRP>--R7--R8
s0/1 fa0/0
192.168.10.1/24 192.168.100.1/24
<-- OSPF Sector EIGRP Sector -->
R5 is redistributing between OSPF network (192.168.10.0/24) and EIGRP network
(192.168.100.1/24).
However, when doing 'sh ip route', the 192.168.10.0/24 and 192.168.100.0/24 are
really NOT ospf, NOR eigrp networks, even though R8 sees 192.168.100.0/24 as
EIGRP route, and R1 sees 192.168.10.0/24 as ospf route. However, to R5, these
networks are neither ospf, nor eigrp, but they are Connected routes.
So redist connected is probably the needed solution on R5 to ensure that
connected networks are carried out as well.. However, I did this on R5 and
192.168.100.0/24 is appearing as OSPF E2 external route on R1/R2, as well as
192.168.10.0/24 appearing as EIGRP EX route on R7/R8 even though I do not
have 'redistribute connected' on R5. R5 just has redistribute ospf under eigrp
process, and redistribute eigrp under ospf process.
Am I missing something?
Thanks for clues!
-J
-- James Jun TowardEX Technologies, Inc. Technical Lead Network Design, Consulting, IT Outsourcing james@towardex.com Boston-based Colocation & Bandwidth Services cell: 1(978)-394-2867 web: http://www.towardex.com , noc: www.twdx.net
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